[EASY][LUCKFOUR] Lucky Four - All About Free

Problem

Kostya likes the number 4 much. Of course! This number has such a lot of properties, like:

  • Four is the smallest composite number;
  • It is also the smallest Smith number;
  • The smallest non-cyclic group has four elements;
  • Four is the maximal degree of the equation that can be solved in radicals;
  • There is four-color theorem that states that any map can be colored in no more than four colors in such a way that no two adjacent regions are colored in the same color;
  • Lagrange’s four-square theorem states that every positive integer can be written as the sum of at most four square numbers;
  • Four is the maximum number of dimensions of a real division algebra;
  • In bases 6 and 12, 4 is a 1-automorphic number;
  • And there are a lot more cool stuff about this number!

Impressed by the power of this number, Kostya has begun to look for occurrences of four anywhere. He has a list of T integers, for each of them he wants to calculate the number of occurrences of the digit 4 in the decimal representation. He is too busy now, so please help him.

Input

The first line of input consists of a single integer T, denoting the number of integers in Kostya’s list.
Then, there are T lines, each of them contain a single integer from the list.

Output

Output T lines. Each of these lines should contain the number of occurences of the digit 4 in the respective integer from Kostya’s list.

Constraints

1 ≤ T ≤ 105

(Subtask 1): 0 ≤ Numbers from the list ≤ 9 - 33 points

(Subtask 2): 0 ≤ Numbers from the list ≤ 109 - 67 points

Examples

Input

5
447474
228
6664
40
81

Output:

4
0
1
1
0

Solution

太简单了…把输入当做字符串处理找出包含几个4即可.

Golang解法

package main

import (
    "fmt"
)

var i, j, t int
var number string
var answers []int

func main() {
    fmt.Scanln(&t)
    answers = make([]int, t)
    for i = 0; i < t; i++ {
        fmt.Scanln(&number)
        answers[i] = 0
        for j = 0; j < len(number); j++ {
            if number[j] == '4' {
                answers[i]++
            }
        }
    }
    for i = 0; i < t; i++ {
        fmt.Println(answers[i])
    }
}

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Published under (CC) BY-NC-SA in categories algorithm  codechef